## Saturday, 28 January 2017

### Pattern printing program

Pattern Number #100

ABCDEDCBA
ABCD DCBA
ABC CBA
AB BA
A A
AB BA
ABC CBA
ABCD DCBA
ABCDEDCBA

The program for the pattern is written in C# programming language and will accept a number as input. The loops will iterate based on the number of entry.

 Pattern printing program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these pattern.

Practical Implementation:

using System;

namespace patternProblem
{
class Pattern100
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");

Console.WriteLine("-----Output-----");
Console.WriteLine();
for (int i = n; i >= 1; i--)
{
for (int j = 1; j <= i; j++)
{
Console.Write((char)(64 + j));
}
if (i == n)
{
for (int j = i - 1; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
}
else
{
Console.Write(" ");
for (int j = i; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
}
Console.WriteLine();
}
for (int i = 2; i <= n; i++)
{
for (int j = 1; j <= i; j++)
{
Console.Write((char)(64 + j));
}
if (i == n)
{

for (int j = i - 1; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
}
else
{
Console.Write(" ");
for (int j = i; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
}
Console.WriteLine();
}

}
}
}

Output:
The input number here is 5. So, the program will iterate five times. The output is shown below:

Enter iteration times:
5
-----Output-----

ABCDEDCBA
ABCD DCBA
ABC CBA
AB BA
A A
AB BA
ABC CBA
ABCD DCBA
ABCDEDCBA
Press any key to continue . . .

For any query, comment us below.

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