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Tuesday, 28 February 2017

SSC CGL 2017 TIER 2 RESULT OUT

SSC CGL 2017 TIER 2 result out with the unexpected cut-off marks. This times SSC indicates that now the competition is very tough.


Steps to check your marks: -
1)    Click on the above link.



2)    Click on the write-up => ("Click here") to see cut off of tier 2 exam

3)    Click on the result => to see the result of tier 2 exam.

4) Download the PDF for future usage.

All the best for your result. Comment your views and discuss what will be the expected cut-off of SSC-CGL 2016 Tier-1. 

REPCO BANK LTD. Recruitment for Assistant Manager and Assistant General Manager 2017

REPCO BANK LTD. Recruitment for Assistant Manager (Scale-I)and Assistant General Manager(Scale III) 2017

Date of Posting: 27/02/2017

Company Name and Type: REPCO BANK LTD

Last date of submission: 10-03-2017.

Hiring Process: Candidates will be selected by
1. Written exam
2. Personal Interview

No. of Vacancy:
1. Assistant Manager Legal (Scale I) - 2
2. Assistant General Manager Legal (Scale III) - 1

Qualification:
1. Assistant Manager Legal (Scale I) - Applicant must Pass with minimum 60% in aggregate in BL/LLB from a recognized university.


2. General Manager Legal (Scale III) – Applicant Graduate in Law from a recognized university and a member of Bar council of the state concerned.



Age Limit
1. Minimum 24 – Maximum 30 years as on 30-06-2016 for Scale I
2. Minimum 30 – Maximum 40 years as on 30-06-2016 for Scale III

Annual CTC: 
1. Assistant Manager Legal (Scale I) – 9.15 CTC
2. Assistant General Manager Legal (Scale III) – 13.85 CTC



Application Fees: For all Candidate, there is a (Non-refundable) fee of Rs. 700. The fee is to be paid by either Bank Pay order or Demand Draft issued by a commercial bank.

How to Apply: All the interested Candidates can post their Bio- Data in English, before the last date of submission.


Important Dates
Last date for Submission as per notification:  10/03/2017

''Note: There is a service bond of 2 years"




Formula based program

Formula #3 (Perimeter and area of semi-circle)

Enter radius: 5
Perimeter of semi-circle: 15.707963267949
Area of semi-circle: 39.2699081698724

The program for the formula is written in C# programming language and will accept a number as radius. Based on the formula it will find out the perimeter and area of semi-circle.
 
Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula
{
    class Formula3     //area and perimeter of semi-circle
    {
        static void Main(string[] args)
        {
            Console.Write("Enter radius: ");
            double radius = Convert.ToDouble(Console.ReadLine());
            double area = 0.0, perimeter = 0.0;

            perimeter = Math.PI * radius;
            area = (Math.PI * (Math.Pow(radius, 2)) / 2);

            Console.WriteLine("Perimeter of semi-circle: {0}", perimeter);
            Console.WriteLine("Area of semi-circle: {0}", area);

            Console.ReadKey();
        }
    }
}

Output:
The input radius here is 7. So, based on the semi-circle formula. The output is shown below:

Enter radius: 7
Perimeter of semi-circle: 21.9911485751286
Area of semi-circle: 76.9690200129499
Press any key to continue . . .


For any query, comment us below.

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Monday, 27 February 2017

Formula based program

Formula #2 (Perimeter and area of circle)

Enter radius: 5
Perimeter of circle: 31.4159265358979
Area of circle: 78.5398163397448

The program for the formula is written in C# programming language and will accept a number as radius. Based on the formula it will find out the perimeter and area of circle.
 
Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula
{
    class Formula2     //area and perimeter of circle
    {
        static void Main(string[] args)
        {
            Console.Write("Enter radius: ");
            double radius = Convert.ToDouble(Console.ReadLine());
            double area = 0.0, perimeter=0.0;

            perimeter = 2* Math.PI * radius;
            area = Math.PI * (Math.Pow(radius, 2));

            Console.WriteLine("Perimeter of circle: {0}", perimeter);
            Console.WriteLine("Area of circle: {0}", area);

            Console.ReadKey();
        }
    }
}

Output:
The input radius here is 7. So, based on the circle formula. The output is shown below:

Enter radius: 7
Perimeter of circle: 43.9822971502571
Area of circle: 153.9380400259
Press any key to continue . . .


For any query, comment us below.

Skip to Main Table – Formula based program

Previous – Formula based program #1


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Keep learning and sharing...

Sunday, 26 February 2017

Formula based program

Formula #1 (Leap year)

Enter a year: 2016
Year is a leap year

The program for the formula is written in C# programming language and will accept a number as input year. Based on the conditions it will check whether the year is a leap year or not.
 
Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula
{
    class Formula1     //Leap year
    {
        static void Main(string[] args)
        {
            Console.Write("Enter a year: ");
            int year = Convert.ToInt32(Console.ReadLine());


            if (((year % 100 != 0) && (year % 4 == 0)) || (year % 400 == 0))
            {
                Console.WriteLine("Year is a leap year");
            }
            else
            {
                Console.WriteLine("Year is not a leap year");
            }

            Console.ReadKey();
        }
    }
}

Output:
The input year here is 2016. So, based on the conditions it will check whether the year is a leap year or not. The output is shown below:

Enter a year: 2016
Year is a leap year
Press any key to continue . . .


For any query, comment us below.

Skip to Main Table – Formula based program


Click imagination hunt to read latest blogs.


Keep learning and sharing...

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