Simple program

Simple program #2 (Check whether a number is even or odd using ternary or conditional operator)

Number: 5, is Odd.
Number: 10, is Even.

The program is written in C# programming language and will accept a number as input. The logic of the program is to find whether the number is even or odd using ternary or conditional operator.
 
Simple program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code the program.

Practical Implementation:

using System;

namespace patternProblem.Simple_program
{
    class Simple2   //Checking Even and Odd number using ternary or conditional operator
    {
        static void Main(string[] args)
        {
            Console.Write("Enter number: ");
            int n = Convert.ToInt32(Console.ReadLine());
            string output = string.Empty;
           
            output = (n % 2 == 0) ? "Number: {0}, is Even." : "Number: {0}, is Odd.";
            Console.WriteLine(output, n);

            Console.ReadKey();
        }
    }
}

Output:
The input number here is 5, which is odd. The output is shown below:

Enter number: 5
Number: 5, is Odd.
Press any key to continue . . .


For any query, comment us below.

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