## Thursday, 22 December 2016

### Pattern printing program

Pattern Number #66

ABCBA
AB BA
A   A
AB BA
ABCBA

The program for the pattern is written in C# programming language and will accept a number as input. The loops will iterate based on the number of entry.

 Pattern printing program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these pattern.

Practical Implementation:

using System;

namespace patternProblem
{
class Pattern66
{
public static void Main()
{
Console.WriteLine("Enter loop iteration times: ");
int n = Convert.ToInt32(Console.ReadLine());
int num = n;
int j;
int i;
int k;
string space = "";
Console.WriteLine("-----Output-----");
Console.WriteLine();

for (i = 1; i <= n; i++, num--)
{
for (j = 1; j <= ((n + 1) - i); j++)
{
if (j >= n)
{
break;
}
else
{
Console.Write((char)(64 + j));
}
}
for (k = 1; k < i; k++)
{
if (k <= i)
{
Console.Write(space.PadRight(k));
}
else
{
Console.Write(space.PadRight(k - 1));
}
}
for (j = num; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
Console.WriteLine();
}
for (i = 2; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (j == n)
{
break;
}
Console.Write((char)(64 + j));
}
for (k = 1; k <= n - i; k++)
{
Console.Write(space.PadRight(k));
}
for (j = i; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
Console.WriteLine();
}

Console.ReadKey();
}
}
}

Output:
The input number here is 3. So, the program will iterate three times. The output is shown below:

Enter loop iteration times:
3
-----Output-----

ABCBA
AB BA
A   A
AB BA
ABCBA
Press any key to continue . . .

For any query, comment us below.

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