## Saturday, 7 January 2017

### Pattern printing program

Pattern Number #81

1
A B
2 3 4
C D E F
5 6 7 8 9

The program for the pattern is written in C# programming language and will accept a number as input. The loops will iterate based on the number of entry.

 Pattern printing program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these pattern.

Practical Implementation:

using System;

namespace patternProblem
{
class Pattern81
{
public static void Main()
{
Pattern81 obj = new Pattern81();
//Different solutions of creating the pattern.

/*(--Tip use the solution one at a time--)*/

//Solution1
obj.Solution1();

//Solution2
//obj.Solution2();
}

public void Solution1()
{
Console.WriteLine("Enter iteration times: ");
int j;
int temp1 = 1;
int temp2 = 1;

Console.WriteLine("-----Output-----");
Console.WriteLine();

for (int i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
Console.Write((char)(64 + temp1) + " ");
temp1++;
}
else
{
Console.Write(temp2 + " ");
temp2++;
}
}
Console.WriteLine();
}
}

public void Solution2()
{
Console.WriteLine("Enter iteration times: ");
int j;
char ch = 'A';
int temp = 1;

Console.WriteLine("-----Output-----");
Console.WriteLine();

for (int i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
Console.Write(ch + " ");
ch++;
}
else
{
Console.Write(temp + " ");
temp++;
}
}
Console.WriteLine();
}

}
}
}

Output:
The input number here is 5. So, the program will iterate 5 times. The output is shown below:

Enter iteration times:
5
-----Output-----

1
A B
2 3 4
C D E F
5 6 7 8 9
Press any key to continue . . .

For any query, comment us below.

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